로그의 밑변환

$\displaystyle \log _{2} 5 \times \log _{5} 3 + \log _{2} \frac{16}{3}$ $\displaystyle = \log _{2} 5 \times \frac{\log _{2} 3}{\log _{2} 5} + \log _{2} \frac{16}{3} = \log _{2} 3 + \log _{2} \frac{16}{3}$ $\displaystyle = \log _{2} \left( 3 \times \frac{16}{3} \right) = \log _{2} 16 = \log _{2} 2 ^{4} = 4$