로그 연립 조건

$\displaystyle \log _{\sqrt{a}} b = 6$에서 $\displaystyle b = \left( \sqrt{a} \right) ^{6} = a ^{3}$ $\log _{4} a + \log _{2} b$$= \log _{4} a + \log _{4} b ^{2}$ $= \log _{4} ab ^{2}$ $= \log _{4} a \left( a ^{3} \right) ^{2}$ $= \log _{4} a ^{7}$ $\log _{4} a = 2$, $a = 4 ^{2} = 16$, $b = 16 ^{3}$ $\displaystyle \log _{2} \frac{b}{a} = \log _{2} \frac{16 ^{3}}{16} = \log _{2} 16 ^{2} = \log _{2} 2 ^{8} = 8$