f ( x ) = ∑ n = 1 17 ∣ x − a n ∣ \displaystyle f ( x ) = \sum\limits _{n = 1} ^{17} \left| x - a _{n} \right| f ( x ) = n = 1 ∑ 17 ∣ x − a n ∣ 은 a i a _{i} a i 들의 중앙값인 a 9 a _{9} a 9 = r 8 = r ^{8} = r 8 에서 최소이므로
r 8 = 16 r ^{8} = 16 r 8 = 16 , r = 2 \displaystyle r = \sqrt{2} r = 2 이다.
최솟값은
m = ∑ n = 1 8 ( 16 − a n ) + ∑ n = 10 17 ( a n − 16 ) \displaystyle m = \sum\limits _{n = 1} ^{8} ( 16 - a _{n} ) + \sum\limits _{n = 10} ^{17} ( a _{n} - 16 ) m = n = 1 ∑ 8 ( 16 − a n ) + n = 10 ∑ 17 ( a n − 16 ) = − ∑ n = 1 8 a n + ∑ n = 10 17 a n \displaystyle = - \sum\limits _{n = 1} ^{8} a _{n} + \sum\limits _{n = 10} ^{17} a _{n} = − n = 1 ∑ 8 a n + n = 10 ∑ 17 a n
인데, ∑ n = 1 8 a n = ∑ n = 1 8 r n − 1 \displaystyle \sum\limits _{n = 1} ^{8} a _{n} = \sum\limits _{n = 1} ^{8} r ^{n - 1} n = 1 ∑ 8 a n = n = 1 ∑ 8 r n − 1 = r 8 − 1 r − 1 = 15 ( 2 + 1 ) \displaystyle = \frac{r ^{8} - 1}{r - 1} = 15 ( \sqrt{2} + 1 ) = r − 1 r 8 − 1 = 15 ( 2 + 1 )
∑ n = 10 17 a n = r 9 ∑ n = 1 8 a n = 16 2 × 15 ( 2 + 1 ) \displaystyle \sum\limits _{n = 10} ^{17} a _{n} = r ^{9} \sum\limits _{n = 1} ^{8} a _{n} = 16 \sqrt{2} \times 15 ( \sqrt{2} + 1 ) n = 10 ∑ 17 a n = r 9 n = 1 ∑ 8 a n = 16 2 × 15 ( 2 + 1 )
∴ \therefore ∴ r m r m r m = 2 × 15 ( 2 + 1 ) ( 16 2 − 1 ) \displaystyle \mathrm{=} \sqrt{2} \times 15 ( \sqrt{2} + 1 ) ( 16 \sqrt{2} - 1 ) = 2 × 15 ( 2 + 1 ) ( 16 2 − 1 ) = 15 ( 30 + 31 2 ) \displaystyle = 15 ( 30 + 31 \sqrt{2} ) = 15 ( 30 + 31 2 )