상용로그 계산

$a$$= \left( \log 3 \right) ^{2} - \left( \log 2 \right) ^{2} = \left( \log 3 - \log 2 \right) \left( \log 3 + \log 2 \right)$ $\displaystyle = \log \frac{3}{2} \times \log 6$ $\displaystyle b = \log _{6} 10 = \frac{1}{\log 6}$ $\displaystyle ab = \log \frac{3}{2} \times \log 6 \times \frac{1}{\log 6} = \log \frac{3}{2}$ 로그의 정의에 의해 $\displaystyle 10 ^{ab} = \frac{3}{2}$