지수법칙 계산

$\displaystyle 10 ^{\frac{2}{3}} \times 2 ^{- \frac{2}{3}} \times 5 ^{- \frac{1}{6}}$ $\displaystyle = \left( 2 \times 5 \right) ^{\frac{2}{3}} \times 2 ^{- \frac{2}{3}} \times 5 ^{- \frac{1}{6}} = 2 ^{\frac{2}{3}} \times 5 ^{\frac{2}{3}} \times 2 ^{- \frac{2}{3}} \times 5 ^{- \frac{1}{6}}$ $\displaystyle = 2 ^{\frac{2}{3} - \frac{2}{3}} \times 5 ^{\frac{2}{3} - \frac{1}{6}} = 2 ^{0} \times 5 ^{\frac{1}{2}} = \sqrt{5}$