곱의 미분

$f \left( x \right) = \left( 2 x + 3 \right) \left( 3 x ^{2} + 2 x + 1 \right)$에서 $f' \left( x \right)$$= 2 \left( 3 x ^{2} + 2 x + 1 \right) + \left( 2 x + 3 \right) \left( 6 x + 2 \right)$ $= \left( 6 x ^{2} + 4 x + 2 \right) + \left( 12 x ^{2} + 22 x + 6 \right)$ $= 18 x ^{2} + 26 x + 8$ $\therefore f' \left( 1 \right) = 18 + 26 + 8 = 52$