f(x)가 다항함수이고 x→∞limx2f(x)=3이므로
f(x)=3x2+ax+b (a,b는 실수)
x→2limx2−x−2f(x)=6이고 x→2lim(x2−x−2)=0이므로
x→2limf(x)=f(2)=0
f(2)=12+2a+b=0, b=−2a−12
f(x)=3x2+ax+(−2a−12)
=(x−2)(3x+6+a)
x→2limx2−x−2f(x)=x→2lim(x−2)(x+1)(x−2)(3x+6+a)
=36+6+a=6
a=6,b=−24
f(x)=3x2+6x−24
f(0)=−24