거듭제곱근 계산

[출제의도] 거듭제곱근과 지수법칙에 관한 계산 능력을 측정한다. $\displaystyle \sqrt{2} \times ^{3} \sqrt{4} \div ^{6} \sqrt{4}$$\displaystyle = 2 ^{\frac{1}{2}} \times 4 ^{\frac{1}{3}} \div 4 ^{\frac{1}{6}}$$\displaystyle = 2 ^{\frac{1}{2}} \times 2 ^{\frac{2}{3}} \div 2 ^{\frac{2}{6}}$$\displaystyle = 2 ^{\frac{1}{2} + \frac{2}{3} - \frac{1}{3}}$$\displaystyle = 2 ^{\frac{1}{2} + \frac{1}{3}}$$\displaystyle = 2 ^{\frac{5}{6}}$$\displaystyle = ^{6} \sqrt{2 ^{5}}$