거듭제곱근 곱 계산

$\displaystyle {}^{3} \sqrt{2 \sqrt{2}} \times ^{6} \sqrt{8}$$\displaystyle = \left( 2 \cdot 2 ^{\frac{1}{2}} \right) ^{\frac{1}{3}} \times ( 2 ^{3} ) ^{\frac{1}{6}}$ $\displaystyle = \left( 2 ^{\frac{3}{2}} \right) ^{\frac{1}{3}} \times 2 ^{\frac{3}{6}}$$\displaystyle = 2 ^{\frac{1}{2}} \times 2 ^{\frac{1}{2}} = 2$