분수부등식 정수해

$f ( x )$와 $y = g ( x - 2 )$가 $x = - 2 , 1 , 2 , 6$에서 만나므로 $f ( x ) - g ( x - 2 ) = k ( x + 2 ) ( x - 1 ) ( x - 2 ) ( x - 6 )$ $( k > 0 )$ $g ( - 1 ) = g ( 2 ) = 0$이므로 $g ( x ) = c ( x + 1 ) ( x - 2 )$ $( c > 0 )$ $g ( x - 2 ) = c ( x - 1 ) ( x - 4 )$ $\displaystyle \frac{f ( x )}{g ( x - 2 )} \leq 1$, $\displaystyle \frac{f ( x ) - g ( x - 2 )}{g ( x - 2 )} \leq 0$, $\displaystyle \frac{k ( x + 2 ) ( x - 1 ) ( x - 2 ) ( x - 6 )}{c ( x - 1 ) ( x - 4 )} \leq 0$ $x \ne 1$, $x \neq 4$이고 $\displaystyle {\frac{k}{c} ( x + 2 ) ( x - 2 ) ( x - 6 ) ( x - 4 )} \leq 0$

$x = - 2 , - 1 , 0 , 2 , 5 , 6$이다. 따라서, 합은 $10$이다.