등비수열 { a n } \left\{ a _{n} \right\} { a n } 의 첫째항을 a a a , 공비를 r r r 라 하면
a n = a × r n − 1 a _{n} = a \times r ^{n - 1} a n = a × r n − 1
lim n → ∞ 4 n × a n − 1 3 × 2 n + 1 = 1 \displaystyle \lim\limits _{n \rightarrow \infty} {\frac{4 ^{n} \times a _{n} - 1}{3 \times 2 ^{n + 1}}} = 1 n → ∞ lim 3 × 2 n + 1 4 n × a n − 1 = 1 에서
lim n → ∞ 4 n × a n − 1 3 × 2 n + 1 \displaystyle \lim\limits _{n \rightarrow \infty} {\frac{4 ^{n} \times a _{n} - 1}{3 \times 2 ^{n + 1}}} n → ∞ lim 3 × 2 n + 1 4 n × a n − 1 = lim n → ∞ a r × ( 4 r ) n − 1 6 × 2 n \displaystyle = \lim\limits _{n \rightarrow \infty} {\frac{\frac{a}{r} \times \left( 4 r \right) ^{n} - 1}{6 \times 2 ^{n}}} = n → ∞ lim 6 × 2 n r a × ( 4 r ) n − 1
= lim n → ∞ a r × ( 2 r ) n − 1 2 n 6 \displaystyle = \lim\limits _{n \rightarrow \infty} {\frac{\frac{a}{r} \times \left( 2 r \right) ^{n} - \frac{1}{2 ^{n}}}{6}} = n → ∞ lim 6 r a × ( 2 r ) n − 2 n 1
(ⅰ) ∣ r ∣ < 1 2 \displaystyle \left| r \right| < \frac{1}{2} ∣ r ∣ < 2 1 일 때
lim n → ∞ ( 2 r ) n = 0 \displaystyle \lim\limits _{n \rightarrow \infty} {\left( 2 r \right) ^{n}} = 0 n → ∞ lim ( 2 r ) n = 0 이므로
lim n → ∞ a r × ( 2 r ) n − 1 2 n 6 = 0 \displaystyle \lim\limits _{n \rightarrow \infty} {\frac{\frac{a}{r} \times \left( 2 r \right) ^{n} - \frac{1}{2 ^{n}}}{6}} = 0 n → ∞ lim 6 r a × ( 2 r ) n − 2 n 1 = 0
이므로 조건을 만족하지 않는다.
(ⅱ) r = 1 2 \displaystyle r = \frac{1}{2} r = 2 1 일 때
lim n → ∞ ( 2 r ) n = lim n → ∞ 1 n = 1 \displaystyle \lim\limits _{n \rightarrow \infty} {\left( 2 r \right) ^{n}} = \lim\limits _{n \rightarrow \infty} {1 ^{n}} = 1 n → ∞ lim ( 2 r ) n = n → ∞ lim 1 n = 1 이므로
lim n → ∞ a r × ( 2 r ) n − 1 2 n 6 = 2 a − 0 6 = a 3 \displaystyle \lim\limits _{n \rightarrow \infty} {\frac{\frac{a}{r} \times \left( 2 r \right) ^{n} - \frac{1}{2 ^{n}}}{6}} = \frac{2 a - 0}{6} = \frac{a}{3} n → ∞ lim 6 r a × ( 2 r ) n − 2 n 1 = 6 2 a − 0 = 3 a
a 3 = 1 \displaystyle \frac{a}{3} = 1 3 a = 1 에서 a = 3 a = 3 a = 3
(ⅲ) r ≤ − 2 r \leq - 2 r ≤ − 2 일 때 수열 { a r × ( 2 r ) n − 1 2 n 6 } \displaystyle \left\{ \frac{\frac{a}{r} \times \left( 2 r \right) ^{n} - \frac{1}{2 ^{n}}}{6} \right\} { 6 r a × ( 2 r ) n − 2 n 1 } 은 진동한다.
(ⅳ) r > 2 r > 2 r > 2 일 때
lim n → ∞ ∣ a r × ( 2 r ) n − 1 2 n 6 ∣ = ∞ \displaystyle \lim\limits _{n \rightarrow \infty} {\left| \frac{\frac{a}{r} \times \left( 2 r \right) ^{n} - \frac{1}{2 ^{n}}}{6} \right|} = \infty n → ∞ lim 6 r a × ( 2 r ) n − 2 n 1 = ∞
이상에서 a = 3 a = 3 a = 3 , r = 1 2 \displaystyle r = \frac{1}{2} r = 2 1 이므로 a n = 3 × ( 1 2 ) n − 1 \displaystyle a _{n} = 3 \times \left( \frac{1}{2} \right) ^{n - 1} a n = 3 × ( 2 1 ) n − 1
a 1 + a 2 = 3 + 3 2 = 9 2 \displaystyle a _{1} + a _{2} = 3 + \frac{3}{2} = \frac{9}{2} a 1 + a 2 = 3 + 2 3 = 2 9