[출제의도] 제곱근의 성질을 이용하여 주어진 식의 값을 구한다.
1 2 − 12 < 0 \displaystyle \frac{1}{2} - 12 < 0 2 1 − 12 < 0 ( 1 2 − 12 ) 2 = − ( 1 2 − 12 ) \displaystyle \sqrt{\left( \frac{1}{2} - 12 \right) ^{2}} = \mathit{-} \left( \frac{1}{2} - 12 \right) ( 2 1 − 12 ) 2 = − ( 2 1 − 12 ) 1 2 + 10 > 0 \displaystyle \frac{1}{2} + 10 > 0 2 1 + 10 > 0 ( 1 2 + 10 ) 2 = 1 2 + 10 \displaystyle \sqrt{\left( \frac{1}{2} + 10 \right) ^{2}} = \frac{1}{2} + 10 ( 2 1 + 10 ) 2 = 2 1 + 10 ( 1 2 − 12 ) 2 − ( 1 2 + 10 ) 2 \displaystyle \sqrt{\left( \frac{1}{2} - 12 \right) ^{2}} - \sqrt{\left( \frac{1}{2} + 10 \right) ^{2}} ( 2 1 − 12 ) 2 − ( 2 1 + 10 ) 2 = − ( 1 2 − 12 ) − ( 1 2 + 10 ) \displaystyle = \mathit{-} \left( \frac{1}{2} - 12 \right) - \left( \frac{1}{2} + 10 \right) = − ( 2 1 − 12 ) − ( 2 1 + 10 ) = − 1 2 + 12 − 1 2 − 10 \displaystyle = \mathit{-} \frac{1}{2} + 12 - \frac{1}{2} - 10 = − 2 1 + 12 − 2 1 − 10 = 1 = 1 = 1